mysql> select name,gender,birthday,salary from employee 
    -> where gender='女'
    -> and (birthday>='1990-01-01' or dep_id = 'D003');
+--------------+--------+------------+--------+
| name         | gender | birthday   | salary |
+--------------+--------+------------+--------+
| 鈴木花子     | 女     | 1990-02-11 | 250000 |
| 高橋良子     | 女     | 1985-11-23 | 300000 |
| 鈴木良枝     | 女     | 1970-05-03 | 450000 |
+--------------+--------+------------+--------+
3 rows in set (0.00 sec)

mysql> select dep_id,name from department where name in 
    -> ('総務部','システム開発部');
+--------+-----------------------+
| dep_id | name                  |
+--------+-----------------------+
| D001   | 総務部                |
| D003   | システム開発部        |
+--------+-----------------------+
2 rows in set (0.00 sec)

mysql> select name from employee where name like '%良%';
+--------------+
| name         |
+--------------+
| 高橋良子     |
| 鈴木良枝     |
+--------------+
2 rows in set (0.01 sec)

mysql> select name from department where name like '_務_';
+-----------+
| name      |
+-----------+
| 総務部    |
+-----------+
1 row in set (0.00 sec)